Rogol usually signs his posts in the Wikimedia mailing list as “Rogol” in scare quotes. But starting with the “fund the endowment” thread, he’s been changing his name in every post.
On Aug 21 it was Reinhard.
On Aug 23 it was Rod.
So what is that about? Just for starters, I would say it’s about contempt. Contempt for the readers, and especially for the volunteers who want to see the project work, and want to be able to use the lists as a communication tool. It’s about letting everyone know that he is playing them for fools, even as they attempt to communicate with him in good faith.
So who is he, what does he do? He’s been around for the last year or so but his contribution history doesn’t say much. He’s only on Meta, and only to stir the pot.
I get it that there is some political component here, that Rogol objects to the WMF using consultants that have also done contracting work for the U.S. Democratic party. But what does he expect? Kellyanne Conway? Bannon? If he has reasonable ideas, why does he not put them forth for discussion. Is there some un-aired grievance? The fact that he chooses to use ‘tactics’ instead of analysis says a lot about whether he considers his objectives to be legitimate.
There’s this last bit also, this bogus thread he started on “News on Wikipedia”, where he asks
“Has the Foundation made a conscious decision to promote Wikipedia as a source of news, and if so, what were the results of its discussions with the Wikipedia and Wikinews communities? Will the Foundation allocate any extra resources to this effort?”
After several knowledgeable people waste their time answering him, his last post on the subject reveals that he is actually canvassing for an RFC on English Wikipedia, one of dozens that are listed every day, but one that
touches on the subject of American politics advances the right-wing agenda (unless this is just a very well done joe-job) that seems so near and dear to his heart. The questions he has wasted everyone’s time with on the mailing list have nothing to do with the RFC, of course.